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Hybridization Trick : Get it in Seconds : Chemistry Easy Short Tricks to find of any Compound – 7tricks

Trick for Hybridization Chemistry

Hybridization:

It is defined as the concept of mixing 2 atomic orbitals make a new atomic orbitals here mixing of two orbitals have same energy . In this process atomic orbitals with equal energy level are mixed than can be mixing of ‘s’ , ‘p’ , ‘d’ orbitals.

Formula :-

               1/2 [V+ M -C + A ]

Here,

V = No. of valence electrons

M = mono valent atom

C = Positive charge 

A = Negative charge

TRICK 1 :-

[  Number of σ (sigma) Bond +  No. of Lone pairs  =  Hybridization ]


IF Sum is 2 then Hybridization is → (SP)

Similarly for 3 → (SP²)  For 4 → (SP³)  For 5 → (SP³d)

For 6 → ( sp²d ²)  For 7 → (SP³d³)

Note : π (pi) bond not consider in Hybridization.

Let’s learn with some Examples

NH3 =

No. of σ Bonds in NH3 {3}  + No. of lone Pairs in N {1}

So Hybridization is 3 + 1 = 4 (SP3)

PCl5  = 

No. of σ Bonds in PCl5  {5} + No. of lone Pairs in P {0}

So Hybridization is 5 + 0 = 5 (SP3d)

CO2  = 

No. of σ Bonds in CO2 {2} + No. of lone Pairs in C {0}

So Hybridization is 2 + 0 = 2 (SP)


TRICK 2 :-


Hybridization

No. of valence e + No. of atom Univalent ± charge
                                  2

 

Note:- (1) Oxygen is not a univalent atom. So if it come then ignore it.

           (2 )Here that sign (±) Show that if  charge on compound is(+ve) then                     we take (-ve)in formula and if charge is (-ve) then take (+ve)      

Let’s learn with some Examples

 NH3 →  (5 +3 +0 ) ÷ 2  =  8 /2 = 4

                        
We got 4 so Hybridization is (SP³)

NOTE:-  Here ,’5′ is valance electrons in Nitrogen and it is  bonded with’3′            .                 univalent atoms (i.e. 3 Hydrogen )
                  And 0 Net Charge on it is zero ‘0’ .


 NH4+    (5+ 4 -1 ) ÷ 2 = 8/2 = 4

So,  Hybridization is (SP3)

NOTE:-  Here this compound has (+ve) charge so we took (-ve) charge      ,                  in Formula.

PCl5 → (5+5+0 )  ÷ 2 =  5  So Hybridization = SP3d

CO2  → (4 + 0 + 0) ÷ 2 = 2 So Hybridization is = SP

NOTE:-  Here we not consider oxygen in formula because Oxygen is not an univalent atom.

IF7    (7+7 + 0) ÷ 2 = 7 So Hybridization is = SP3d3

 

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